2x-x^2-8=0

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Solution for 2x-x^2-8=0 equation:


Simplifying
2x + -1x2 + -8 = 0

Reorder the terms:
-8 + 2x + -1x2 = 0

Solving
-8 + 2x + -1x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
-1 the coefficient of the squared term: 

Divide each side by '-1'.
8 + -2x + x2 = 0

Move the constant term to the right:

Add '-8' to each side of the equation.
8 + -2x + -8 + x2 = 0 + -8

Reorder the terms:
8 + -8 + -2x + x2 = 0 + -8

Combine like terms: 8 + -8 = 0
0 + -2x + x2 = 0 + -8
-2x + x2 = 0 + -8

Combine like terms: 0 + -8 = -8
-2x + x2 = -8

The x term is -2x.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2x + 1 + x2 = -8 + 1

Reorder the terms:
1 + -2x + x2 = -8 + 1

Combine like terms: -8 + 1 = -7
1 + -2x + x2 = -7

Factor a perfect square on the left side:
(x + -1)(x + -1) = -7

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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